How do you find the maximum height of a projectile? Well there are a few ways you could go about it. You could figure it out from eq. 5.17, but let's instead do it from eq. 5.14. At the maximum height, the y component of the velocity is zero. So we can solve for , the time when this happens. It's just . Now plug this into eq. 5.16 to get the maximum height, again with :

Mon Jan 6 00:05:26 PST 1997