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The shape of the trajectory

So now we know how the position of an object in free fall depends on time. But what if we want to know the shape of arc drawn out by the object? We want to know how y depends on x. Let's take the initial position of the object to be at the origin tex2html_wrap_inline1940 . Then we just eliminate time in eqs. 5.15 and 5.16. So first solve for time in eq. 5.15, that gives tex2html_wrap_inline1942 . Substitute this into 5.16 and we get:

  equation456

This is the equation of a parabola. A stream of water, such as produced by a garden hose, or a fountain, gives us nice conformation of these parabolic shapes.



Joshua Deutsch
Mon Jan 6 00:05:26 PST 1997