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Totally inelastic collisions

Suppose Bobby is cycling east at 5m/s, and Lisa is cycling north at 10m/s happen to collide. They and their bikes get all tangled up and start moving together. What's the velocity of the Bobby-Lisa-bicycle glob right after the collision? Let's take the combined mass of Bobby and his bike to be tex2html_wrap_inline1357 and Lisa and her bike to be tex2html_wrap_inline1359 . (Don't worry, Bobby and Lisa are fine. This is not a real examaple.)

To figure this out, we'll use conservation of momentum, as we claimed that to a good approximation, we can ignore other forces during the collision.

Before:
The total momentum tex2html_wrap_inline1361
After:
The tex2html_wrap_inline1363 . where tex2html_wrap_inline1365 denotes the final velocity, right after the collision.

Equating these two expressions (since momentum is conserved) we have

equation356

Now tex2html_wrap_inline1367 and tex2html_wrap_inline1369 so we get

equation359

The combined mass goes shooting off in the north-east direction.

This is an example of a totally inelastic collision. When the two masses hit, they stick together. The final velocity is just the center of mass velocity of the system, since the center of mass velocity is constant for any process obeying conservation of momentum.

Momentum is conserved but in general, energy is not. You could calculate the change in kinetic energy during this collision and would find that it is negative. What happens to this energy? It mostly goes into heat, some of it goes into sound waves. The scrunching sound that you hear is powered by the initial kinetic energy of our two unfortunate bicyclists.



Joshua Deutsch
Fri Jan 17 12:19:41 PST 1997