How do you find the maximum height of a projectile? Well there
are a few ways you could go about it. You could figure it out
from eq. 5.17, but let's instead do it from eq.
5.14. At the maximum height, the y component of the
velocity is zero. So we can solve for 
, the time when this happens.
It's just 
. Now plug this into eq. 5.16 to
get the maximum height, again with 
:
