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proof:

Say the object is composed of N pieces with masses tex2html_wrap_inline839 . Call the displacment vectors between these pieces and the axis distances tex2html_wrap_inline841 between the pieces and the axis, then

equation224

When the axis is displaced by a vector tex2html_wrap_inline843 , then we want to compute

  equation228

where tex2html_wrap_inline845 is the displacment vectors between these pieces and the new axis.

Let's relate the tex2html_wrap_inline845 to tex2html_wrap_inline849

equation233

And since tex2html_wrap_inline851 (dropping the subscript for convenience)

equation235

Now plugging this into 1.57 we have

equation239

The last term contains tex2html_wrap_inline853 . Dividing this by M, this would be the center of mass in the plane perpendicular to the axis. It is reckoned about the center of mass, so by definition, this must be zero. That is, if you calculate the center of mass of an object when the origin of the coordinate system is the center of mass, you get zero. So we only have the first two terms in the above equation. So we get eqn. 1.55.



Joshua Deutsch
Wed Jan 22 17:07:34 PST 1997